Utente:Sophia Sansone/Sandbox: differenze tra le versioni

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Etichetta: Editor wikitesto 2017
Etichetta: Editor wikitesto 2017
Riga 124:
+ 98,06 u.
- 65 u.
</quiz>
 
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{Bilancia questa reazione: H<sub><small>3</small></sub>PO<sub><small>4</small></sub> + Ca(OH)<sub><small>2</small></sub> → Ca<sub><small>3</small></sub>(PO<sub><small>4</small></sub>)<sub><small>2</small></sub> + H<sub><small>2</small></sub>O
|type="()"}
- H<sub><small>3</small></sub>PO<sub><small>4</small></sub> + 3Ca(OH<sub><small>2</small></sub>)<sub><small>2</small></sub> → Ca<sub><small>3</small></sub>(PO<sub><small>4</small></sub>) + 6H<sub><small>2</small></sub>O
- 2H<sub><small>3</small></sub>PO<sub><small>5</small></sub> + 3Ca(OH)<sub><small>2</small></sub> → Ca<sub><small>3</small></sub>(PO<sub><small>4</small></sub>)<sub><small>2</small></sub> + 6H<sub><small>2</small></sub>O
- 2H<sub><small>2</small></sub>PO<sub><small>4</small></sub> + 3Ca(OH)<sub><small>4</small></sub> → Ca<sub><small>3</small></sub>(PO<sub><small>4</small></sub>) + 6H<sub><small>2</small></sub>O
+ 2H<sub><small>3</small></sub>PO<sub><small>4</small></sub> + 3Ca(OH)<sub><small>2</small></sub> → Ca<sub><small>3</small></sub>(PO<sub><small>4</small></sub>)<sub><small>2</small></sub> + 6H<small><sub>2</sub></small>O
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{ Calcola la massa molecolare dei seguenti composti (scrivere il risultato usando la virgola, non il punto, inserendo l'unità di misura):
|type="{}"}
Al<sub><small>2</small></sub>(SO<sub><small>4</small></sub>)<sub><small>3</small></sub> { 342,14 u }
H<sub><small>2</small></sub>SO<sub><small>4</small></sub> { 98,06 u }
Na<sub><small>2</small></sub>SO<sub><small>4</small></sub> { 142,04 u }
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<quiz display=simple>
{Bilancia questa reazione: Ba(OH)<sub><small>2</small></sub> + HClO<sub><small>4</small></sub> → Ba(ClO<sub><small>4</small></sub>)<sub><small>2</small></sub> + H<sub><small>2</small></sub>O
|type="()"}
+ Ba(OH)<sub><small>2</small></sub> + 2HClO<sub><small>4</small></sub> → Ba(ClO<sub><small>4</small></sub>)<sub><small>2</small></sub> + 2H<sub><small>2</small></sub>O
- Ba(OH)<sub><small>3</small></sub> + 2HClO<sub><small>2</small></sub> → Ba(ClO<sub><small>4</small></sub>)<sub><small>2</small></sub> + 2H<sub><small>2</small></sub>O
- Ba(OH)<sub><small>2</small></sub> + 2HClO<sub><small>4</small></sub> → Ba(ClO<sub><small>4</small></sub>)<sub><small>4</small></sub> + 2H<sub><small>3</small></sub>O
- 2Ba(OH) + 2HClO<sub><small>4</small></sub> → 2Ba(ClO<sub><small>4</small></sub>) + 2H<sub><small>2</small></sub>O
</quiz>